Rectilinear Motion Problems And Solutions Mathalino Upd Link ★ Free Forever

v = ds/dt = 4t - t³/3 + 3 → ds = (4t - t³/3 + 3) dt s(t) = ∫(4t - t³/3 + 3) dt = 2t² - t⁴/12 + 3t + D At t=0, s=2 → 2 = 0 - 0 + 0 + D → D=2. Thus s(t) = 2t² - t⁴/12 + 3t + 2 m.

Given: u = 0, v = 72 km/h = 20 m/s, t = 10 s Using , we get: 20 = 0 + a(10) a = 2 m/s^2 rectilinear motion problems and solutions mathalino upd

Displacement from t=0 to t=2: [ \int_0^2 (2t-4) dt = [t^2 - 4t]_0^2 = (4-8) - 0 = -4 \ \textm ] Distance part 1 = ( | -4 | = 4 ) m. v = ds/dt = 4t - t³/3 +

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